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Find an equation of the perpendicular bisector of the line segment joining the points A(1,4) and B(7,-2)

User Davidmpaz
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2 Answers

3 votes

Answer:

y=x+5

Explanation:

Got this question from Precalculus Fifth Edition: Mathematics for Calculus by James Stewart, Lothar Redlin, and Saleem Watson

User Bitdiot
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7 votes

Start by finding the slope and y-intercept:

slope (y1-y2) / (x1-x2) so:

-2-4 = -6

7-1 = 6

slope = -6/6 or -1

using this information we can find the y-intercept by using the point 1,4 and applying the slope. We know the slope is -1, so if we go backwards from the point 1,4 up one and left one, we hit the y-axis at 0,5. From this we now know our equation:

y = mx + b

m = slope

b = y-intercept

y = -x + 5

To find a perpendicular line, you have to find the reverse reciprocal of the slope, so in this case it is 1. So in this case we could say an equation for a perpendicular line is:

y = x + 5

User Kodie Grantham
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