2 Answers

Jon Bright · Answer 1 · 2019-03-31T04:53:47+0000

Answer: The equivalent resistance in this circuit
$15\Omega$

Step-by-step explanation:

In the given circuit, resistors are arranged in series,so the equivalent resistance in the circuit will be given as:

$R_1=2.0 \Omega,R_2=3.0 \Omega,R_3=4.0 \Omega,R_4=6.0\Omega$

R_(eq)=R_1+R_2+R_3+R_4

$R_(eq)=2.0\Omega+3.0\Omega+4.0\Omega+6.0\Omega=15\Omega$

The equivalent resistance in this circuit
$15\Omega$

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