234k views
4 votes
What is the cantation of a line that passes through the point (-3,-11) and is parallel to the line 2x -y = 4

User Karen
by
6.1k points

2 Answers

5 votes

Final answer:

To find the equation of a parallel line, use the same slope as the original line and apply it to the point-slope form with the given point. The resulting equation for the line parallel to 2x - y = 4 and passing through (-3, -11) is y = 2x - 17.

Step-by-step explanation:

To find the equation of a line that is parallel to another, we must ensure they have the same slope. The line given is 2x - y = 4. To find its slope, we can rewrite it in slope-intercept form (y = mx + b) by solving for y. The equation becomes y = 2x - 4. The slope (m) here is 2. Now, since parallel lines have equal slopes, our new line will also have a slope of 2.

Next, we use the point-slope form of a linear equation to find the equation of the line passing through the point (-3, -11) which is y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point. Substituting m with 2 and (x1, y1) with (-3, -11), we get y - (-11) = 2(x - (-3)), simplifying to y + 11 = 2(x + 3). Lastly, simplifying the equation we get y = 2x - 6 - 11, hence, the equation of the line is y = 2x - 17.

User Ramone
by
5.8k points
1 vote

Answer:

The equation is y = 2x - 5

Step-by-step explanation:

First we have to find the slope of the line. In order to do so, solve the first equation for y.

2x - y = 4

-y = -2x + 4

y = 2x - 4

This gives us a slope of 4. Given that information, we now can plug the slope and point into point-slope form and get the final equation.

y - y1 = m(x - x1)

y - -11 = 2(x - -3)

y + 11 = 2x + 6

y = 2x - 5

User Shishir Morshed
by
5.9k points