Question

`x^(2) -(x)/(5) + 2 = 0`

Answer 1

x^2 - x/5 + 2 = 0

Subtract 2 from both sides.

x^2 - x/5 = -2

Multiply all terms by 5.

5x^2 - x = -10

Add 10 to both sides.

5x^2 - x + 10 = 0

We can now apply the quadratic formula:

`-b ± (√(b^2 - 4ac) )/(2a)`

1 ± (√ 1 - 200) / 10

1 ± √-199 / 10

1 ± i√199 / 10

The solutions are equal to 1 + or - i times the square root of 199 divided by 10.