Question

A miner finds a piece of shiny metal while panning for gold. He finds that the metal has a volume of 1.3ml and a mass of 25.1g. What is the density of the metal? (1 decimal place) What did he find?

Answer 1

Answer: 19.3 g/mL, or 19,300 kg/m^3

Step-by-step explanation:

The density of the piece of metal is given by:

`d=(m)/(V)`

where

m = 25.1 g is the mass of the piece of metal

V = 1.3 mL is the volume

Substituting the numbers into the formula, we find

`d=(m)/(V)=(25.1 g)/(1.3 mL)=19.3 g/mL`

If we want to convert into SI units:

`d=19.3 g/mL = 19.3 g/cm^3 \cdot (0.001 kg/g)/(1\cdot 10^(-6) m^3/cm^3)=19300 kg/m^3`