Question

What is the volume of a cone with a height of 9.5 inches and a radius of 8 inches? Cone V = 1 3 Bh 1. Rewrite the formula for the base area: V = 1 3 πr2h

2. Substitute the values into the formula: V = 1 3 π(82)(9.5)
3.Evaluate the power:V = 1 3 π(64)(9.5)
4.Simplify using multiplication: V = 1 3 π(608)
The cone has a volume of?

Answer 1

`202.666\pi inches^3`

Explanation:

Given :

Height of cone = 9.5 inches

Radius of cone = 8 inches

To Find: Volume of cone

Solution:

Volume of cone =
`(1)/(3)\pi r^2 h`

=
`(1)/(3)\pi (8)^2 (9.5)`

=
`\pi 202.666`

Thus the volume of the given cone is
`202.666\pi inches^3`

Answer 2

636.4 in³

Explanation:

Volume of a cone is given by:

`V = (1)/(3)\pi r^2 h`

where r is the radius of the base of the cone and h is its height.

It is given that, the radius of the base of the cone is, r = 8 in

The height of the cone is, h = 9.5

`\Rightarrow V = (1)/(3) * 3.14 * (8)^2 (9.5) = 636.4 in^3`

Thus, the volume of the cone is 636.4 in³