Question

Factor the polynomial. 14x^2y+4x-7xy-2=(2x-1)(

Answer 1

Hello from MrBillDoesMath!

Answer: (2x -1) (7xy+2)

Steps:

Rewrite the equation as follows:

(14x^2y - 7xy) + (4x -2)

Factor 7xy from the first term and 2 from the second term:

7xy(2x -1 ) + 2 ( 2x -1)

Factor (2x-1) from each term to get

(2x -1) ( 7xy + 2)

You can multiply this out to verify the answer.

Regards, MrB

Answer 2

The factorization of the polynomial is given by:

`4x^2y+4x-7xy-2=(7xy+2)(2x-1)`

Explanation:

We are given a polynomial expression in terms of two variables x and y as follows:

`14x^2y+4x-7xy-2`

Now, we combine the first and third term of the expression and second and fourth term of the expression as follows:

`14x^2y+4x-7xy-2=14x^2y-7xy+4x-2`

Now on taking out the common term from the expression we have:

`14x^2y+4x-7xy-2=7xy(2x-1)+2(2x-1)`

which on further simplifying gives us:

`4x^2y+4x-7xy-2=(7xy+2)(2x-1)`