Answer:
1.0125 x 10^19
Step-by-step explanation:
current flowing through conductive wire= 9mA = 9 x 10^ -3 A
charge passing per 3 min
Q = It
= 9 x 10^ -3 x (3 x 60)
= 1.620 C
no of electrons in charge
Q = ne
1.620 = n x 1.6 x 10 ^ -19
n. = 1.0125 x 10 ^19