Question

Mrs. Jones buys two toys for her son. The probability that the first toy is defective is `1/3`, and the probability that the second toy is defective given that the first toy is defective is `1/5`. What is the probability that both toys are defective?

Answer 1

Answer: 1/15

Explanation:

Answer 2

Answer:
`(1)/(15)`

Explanation:

Let A denote the event of first toy is defective and B denote the second toy is defective .

Given: The probability that the first toy is defective
`:\ P(F)=(1)/(3)`

The probability that the second toy is defective given that the first toy is defective =
`P(B|A)=(1)/(5)`

The formula to calculate the conditional probability is given by :

`P(B|A)=(P(A\cap B))/(P(A))\\\\\Rightarrow\ P(A\cap B)=P(B|A)* P(A)\\\\\Rightarrow\ P(A\cap B)=(1)/(5)*(1)/(3)=(1)/(15)`

Hence, the required probability :
`(1)/(15)`