2 Answers

Mbadd · Answer 1 · 2019-02-12T02:39:48+0000

Answer:
(1)/(15)

Explanation:

Let A denote the event of first toy is defective and B denote the second toy is defective .

Given: The probability that the first toy is defective
$:\ P(F)=(1)/(3)$

The probability that the second toy is defective given that the first toy is defective =
P(B|A)=(1)/(5)

The formula to calculate the conditional probability is given by :

$P(B|A)=(P(A\cap B))/(P(A))\\\\\Rightarrow\ P(A\cap B)=P(B|A)* P(A)\\\\\Rightarrow\ P(A\cap B)=(1)/(5)*(1)/(3)=(1)/(15)$

Hence, the required probability :

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