Answer:
42°C
Explanation:
The formula relating the heat (q) absorbed or released by an object, its mass (m), and the temperature change (ΔT) is
q = mCΔT Divide both sides by mC and switch
ΔT = q/(mC)
where
C = the specific heat capacity of the object
1. Calculate the change in temperature
q = 8360 J
m = 100 g
C = 4.184 J·°C⁻¹g⁻¹
ΔT = 8360/(100 × 4.184)
ΔT = 8360/418.4
ΔT = 19.98 °C
2. Calculate the final temperature
ΔT = T₂ -T₁ Add T₁ to each side and switch
T₂ = T₁ + ΔT
where T₂ and T₁ are the final and initial temperatures
T₁ = 22 °C
ΔT = 19.98 °C
T₂ = 22 + 19.98
T₂ = 42 °C