Consider rectangular box with
- length x units (x≥0);
- width 3 units;
- height (8-x) units (8-x≥0, then x≤8).
The volume of the rectangular box can be calculated as
![V_(box)=\text{length}\cdot \text{width}\cdot \text{height}.](https://img.qammunity.org/2019/formulas/mathematics/high-school/vsy5eengwsfgfkhno8ny1ir0emnq3kzcew.png)
In your case,
![V_(box)=3\cdot x\cdot (8-x).](https://img.qammunity.org/2019/formulas/mathematics/high-school/5j5tzhssna8o6r4rs7jblijl0j26wk70mv.png)
Note that maximal possible value of the height can be 8 units (when x=0 - minimal possible length) and the minimal possible height can be 0 units (when x=8 - maximal possible length).
From the attached graph you can see that the greatest x-intercept is x=8, then the height will be minimal and lenght will be maximal.
Then the volume will be V=0 (minimal).
Answer: correct choices are B (the maximum possible length), C (the minimum possible height)