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Given the equation-4x+2y=-2 what is the Equation of the line perpendicular to the line that goes through the point (2,-2)

Given the equation 3x+5y=-15 what is the Equation of the line perpendicular to the line that goes through the point (-3,-5)

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Answer:

The equation of the perpendicular line would be y = -1/2x - 1

Explanation:

In order to find this line, we must first find the slope of the original line. We do this by solving for y.

-4x + 2y = 2

2y = 4x + 2

y = 2x + 1

This shows us a slope of 2. TO find the perpendicular slope, we use the opposite and reciprocal. This means we negative 2 to get -2 and then we flip it to get -1/2. Now that we have this, we can use the slope and the point in point-slope form to get the equation.

y - y1 = m(x - x1)

y + 2 = -1/2(x - 2)

y + 2 = -1/2x + 1

y = -1/2x - 1

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