Question

Find the solutions to the equation below, Check all that apply. 16x^2-64=0

Answer 1

x= 2, -2 is the answer

Answer 2

The solution of the given equation is:

x=2 and x= -2

Explanation:

We are given an quadratic equation as:

`16x^2-64=0`

Now we are asked to find the solution of this equation i.e. we are asked to find the possible value of x that satisfy this equation.

`16x^2-64=0\\\\\\16(x^2-4)=0\\\\\\x^2-4=0\\\\(x-2)(x+2)=0`

Since, we know that:

`a^2-b^2=(a-b)(a+b)`

Hence, we have:

x=2 or x= -2

Hence, the solution of the equation are:

2 or -2.