We are given that
triangle KMN and triangle PRT are congruent
so, their corresponding sides must be equal
so, we can get
![KM=PR](https://img.qammunity.org/2019/formulas/mathematics/high-school/tfrqtfaz7qhu7c19ct6cyi5ijmegvl9n48.png)
![MN=RT](https://img.qammunity.org/2019/formulas/mathematics/high-school/yysjwv62lim0q0leopsl3r3aiw8g2fymwv.png)
![NK=TP](https://img.qammunity.org/2019/formulas/mathematics/high-school/rej2jij0njbu19vxqp4zu8g17ytq2fztv0.png)
we are given
![KM=15](https://img.qammunity.org/2019/formulas/mathematics/high-school/ukd6tm6td1xx44haoffxgr3orgxl44w0nb.png)
![MN=20](https://img.qammunity.org/2019/formulas/mathematics/high-school/8muje48yp798hkh1vkmmjhqm92kzh0ws73.png)
![NK=25](https://img.qammunity.org/2019/formulas/mathematics/high-school/xguno2qrha1n7eqwzhgm6gmv2m11lar0b9.png)
![RT=3x-1](https://img.qammunity.org/2019/formulas/mathematics/high-school/96cwfig83eqv48foxm6gq8j7k41p4j29ok.png)
now, we can plug this value
![MN=RT=3x-1](https://img.qammunity.org/2019/formulas/mathematics/high-school/ec6d6vfk6jkdp2cdi080jt5wioru58c5pd.png)
![20=3x-1](https://img.qammunity.org/2019/formulas/mathematics/high-school/ccy4lpl50uktf4mprbvianjmxoedtin8gh.png)
now, we can solve for x
Add 1 on both sides
![20+1=3x-1+1](https://img.qammunity.org/2019/formulas/mathematics/high-school/npw9e3tpiq20hx4qscjeri84ngxmf0yzfd.png)
![21=3x](https://img.qammunity.org/2019/formulas/mathematics/high-school/fc1jdi1xftu5w1v922x7rrjkqrp5b3uvy3.png)
Divide both sides by 3
and we get
..............Answer