61.9k views
4 votes
What is the area of a triangle whose vertices are D(3, 3) , E(3, −1) , and F(−2, −5) ?

units²

1 Answer

5 votes

The points given are:
D=(3,3),E=(3,-1),F=(-2-5)

Area of the triangle is given by:


A = (1)/(2)| ( x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2) )|


A = (1)/(2) |(3(-1+5) + 3(-5-3) -2(3+1))|


A = (1)/(2)|(3(4) + 3(-8) -2(4))|


A = (1)/(2) |( 12 -24 -8))|


A = (1)/(2) |( -20)|


A = |-10|


A = 10 \ units^2

User Jsb
by
5.4k points