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4 votes
Help please on 3 and 4

Help please on 3 and 4-example-1

2 Answers

3 votes

Hi,

For 3:

Instead of multiplying right hand side with 7/4, it was done with 4/7.

So, correct solution would be:


\left((7)/(4)\right)(4)/(7)m=(7)/(4)22\Rightarrow m=(7\cdot 11)/(2)=\frac{77}2.

For 4: on the left hand side, instead of n, correct value is --n,

then --n = 18 |·(--1) ⇒ n = --18.

Have you understood ?

Green eyes.

User CAdaker
by
8.4k points
3 votes

In (3) we're supposed to multiply both sides by 7/4 but the 7/4 got flipped over on the right hand side.

In (4) we lost a minus sign going from the second to third step. We would have been better off multiplying both sides by -6.


User David King
by
8.2k points

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