179k views
3 votes
3 exponet 8×4+9÷1×56+57

User Lim CHAN
by
7.6k points

1 Answer

3 votes
You would use PEMDAS

But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57

Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57

Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57

Now you can add all of the numbers together
32➕504=536
536➕57=593

Your answer is 593

Hope this helps! :3
User Ergin
by
8.9k points

Related questions

asked Apr 19, 2024 234k views
MrsBookik asked Apr 19, 2024
by MrsBookik
7.8k points
2 answers
4 votes
234k views
asked Mar 27, 2024 85.1k views
Lyuda asked Mar 27, 2024
by Lyuda
8.4k points
1 answer
1 vote
85.1k views
asked Nov 5, 2024 61.3k views
Sworded asked Nov 5, 2024
by Sworded
9.0k points
1 answer
4 votes
61.3k views