Question

What is the solution set for 2x^2+20=8

Answer 1

`2x^2+20=8\qquad|-20\\\\2x^2=-12\qquad|:2\\\\x^2=-6 < 0\\\\\text{No real solution}\\----------------------------\\\text{In complex numbers}\\\\i=√(-1)\\\\x^2=-6\to x=\pm√(-6)\\\\x=-√((6)(-1))\ \vee\ x=√((6)(-1))\\\\x=-\sqrt6\cdot√(-1)\ \vee\ x=\sqrt6\cdot√(-1)\\\\\boxed{x=-i\sqrt6\ \vee\ x=i\sqrt6}`