Question

Type the correct answer in each box. Use numerals instead of words.

The zeros of the function f(1) = -(x + 1)(0 - 3)(x + 2) are –1, 3, and __and the y-intercept of the function is located at (0,__)
Pls help

Answer 1

Given:

Consider the given function is
`f(x)=-(x+1)(x-3)(x+2)`.

To find:

The remaining zero and y-coordinate of y-intercept.

Solution:

We have,

`f(x)=-(x+1)(x-3)(x+2)`

For zeros,
`f(x)=0`.

`-(x+1)(x-3)(x+2)=0`

`(x+1)(x-3)(x+2)=0`

`(x+1)=0,(x-3)=0,(x+2)=0`

`x=-1,x=3,x=-2`

So, three zeros of given function are -1, 3 and -2.

Putting x=0 in the given function, we get

`f(0)=-(0+1)(0-3)(0+2)`

`f(0)=-(1)(-3)(2)`

`f(0)=-(-6)`

`f(0)=6`

So, the y-coordinate of y-intercept of the given function is 6. It means the y-intercept is at point (0,6).

Therefore, the zeros of the function
`f(x)=-(x+1)(x-3)(x+2)` are –1, 3, and -2 and the y-intercept of the function is located at (0,6).