Solve for x. -15x+60<105 and 14x+11<-31 A). x<-3 B).x>-3 C).x=-3 D). there are no solutions E). all caluse of x are dolutions

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asked Sep 23, 2019 108k views

2 Answers

Hosselausso · Answer 1 · 2019-09-28T14:01:55+0000

-15x+60<105 and 14x+11<-31

-15x+60<105 subtract 60 from each side

-15x <45

divide by -15 (flips the inequality)

x>3

14x+11<-31

subtract 11 from each side

14x < -42

divide by 14

x<-3

Answer : there are no solutions since x>3 and x<-3 they are mutually exclusive (they both can't happen at the same time)