Question

How to graph equation y+2=3/2(x+4)

Answer 1

Equation simplifies to y=3/2x+4, so y-int=4 and slope=3/2 (up 3/right 2)

3 plots --> (-2, 1), (0, 4), (3, 6)

Answer 2

For this case we have the following equation:

`y + 2 =(3)/(2) (x + 4)`

We can rewrite it in the way

`y = mx + b`

Where m is the slope and b represents the cut point.

So:

`y =(3)/(2)(x + 4) -2`

`y =(3)/(2)x +(12)/(2)-2`

`y =(3)/(2)x + 6-2`

`y =(3)/(2)x + 4`

`m =(3)/(2)\\b = 4`

To graph, we look for two points through which the line passes:

Doing
`x = 0` we have:

`y =(3)/(2)(0) +4`

`y = 4`

So, we have the point:
`(x1, y1) = (0,4)`

By doing
`y = 0` we have:

`0 =(3)/(2)x + 4`

`-4 =(3)/(2)x`

`-8 = 3x`

`x =-(8)/(3)`

So, we have the point:
`(x2, y2) = (-(8)/(3),0)`

We locate
`(x1, y1) = (0,4)` and
`(x2, y2) = (-(8)/(3),0)` in a coordinate plane and the graph is attached.

Answer:

See attached image