Answer:
a_n=a_(n−1)+1.4 , where a_1=4.4
Explanation:
Given a sequence as
4.4, 5.8, 7.2, 8.6, 10, …
We find that first term is 4.4
II term = 5.8 = 4.4+1.4
III term = 7.2 = 5.8+1.4
Iv term = 8.6 = 7.2+1.4
V term = 10.0 = 8.6+1.4
i.e. each term is got by adding 1.4 to the previous term.
In other words, this is an arithmetic sequence with I term =4.4 and d = common difference =1.4
I term = a_1 = 4.4
and a_2 = a_1+1.4 and so on.
Hence correct answer is
a_n=a_(n−1)+1.4 , where a_1=4.4