Question

A line with a slope of 1/10 passes through the points (-4,-4) and (6,s) .what is the value of s.

Answer 1

`\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{s}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{s-(-4)}{6-(-4)}=\stackrel{\stackrel{slope}{\downarrow }}{\cfrac{1}{10}}\implies \cfrac{s+4}{6+4}=\cfrac{1}{10} \\\\\\ \cfrac{s+4}{10}=\cfrac{1}{10}\implies s+4=\cfrac{10}{10}\implies s+4=1\implies s=-3`