Question

HURRY 30 PTS

What is the equation of the graphed line written in standard form?
A. 3x + y = –5
B. x + 3y = –5
C. 3x – 5y = –15
D. 5x – 3y = 15

Answer 1

its d on edgunity

Explanation:

Answer 2

D

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, 0 ) and (x₂, y₂ ) = (0, - 5 )

m =
`(-5-0)/(0-3)` =
`(5)/(3)`

line crosses y-axis at (0, - 5 ) hence c = - 5

y =
`(5)/(3)` x - 5 ← in slope-intercept form

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

rearrange slope-intercept form into standard form

multiply all terms by 3

3y = 5x - 15 ( subtract 3y and add 15 to both sides )

5x - 3y = 15 ← in standard form → D