Question

1​​. 2​​. Two small pitchers and one large pitcher can hold 8 cups of water. One large pitcher minus one small pitcher constitutes 2 cups of water. How many cups of water can each pitcher hold?

Answer 1

Answer: Larger pitcher holds 4 Cups of water, and the Smaller pitchers hold 2 Cups of water. ======> Answer: X = 4, Y = 2

Explanation:

Solve the Equation:

x + 2y = 8

x - y = 2

Solve:

x + 2y = 8; x - y = 2

Solve:

x + 2y = 8 for x

x + 2y + -2y = 8 + -2y

Add -2y both sides:

x = -2y + 8

Substitute:

-2y + 8 for x in x - y = 2

x - y = 2

-2y + 8 - y = 2

-3y + 8 = 2

Simplify both sides:

-3y + 8 + -8 = 2 + -8

Add: -8 both sides

-3y = -6

-3y/ -3 = -6/-3

Divide both sides by -3:

y = 2

Step 2: Substitute:

2 for y in x = -2y + 8

x = 2y + 8

x = (-2 )(2) + 8

x = 4

Simplify both sides of equation:

Therefore, your answer for the larger pitcher holds, x = 4 cups of water, while the smaller pitchers hold, y = 2 cups of water.

Hope that helps!!!!! : )

Answer 2

Hey MonkeyForLife,

Question:

Two small pitchers and one large pitcher can hold 8 cups of water. One large pitcher minus one small pitcher constitutes 2 cups of water. How many cups of water can each pitcher hold?

We Know:

All 3 picthers hold 8 cups together.

Solution:

8 - 2 = 6

6 - 4 = 2

2 - 2 = 0

Answer:

Small pitchers hold 2 cups.

Large pitchers hold 4 cups.

4 + 2 + 2 = 8