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If (a+b)^2 = 37 and ab=5 what is a^2 + b^2

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(a+b)^2 = 37a^2 + 2ab + b^2 = 37\\a^2 + 2(5) + b^2 = 37\\a^2 + b^2 + 10 = 37\\a^2 + b^2 = 27


Answer: 27

User Stoner
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4 votes

(a+b)^2 = 37

a^2 + 2ab + b^2 = 37

Substitute ab = 5 into a^2 + 2ab + b^2 = 37

a^2 + 2(5) + b^2 = 37

a^2 + b^2 + 10 = 37

a^2 + b^2 = 27

Answer

a^2 + b^2 = 27

User Ndemir
by
7.8k points

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