Question

In standardizing the solution of aqueous sodium hydroxide, a chemist overshoots the end point and adds too much naoh(aq). would this error result in a calculated concentration of naoh that was overestimated or underestimated? explain your reasoning.

Answer 1

Answer: Concentration of NaOH calculated will be underestimated.

Step-by-step explanation:

End point is an observational point , which tells us about the completion of reaction between the titrant (solution in burette) and titre(solution in conical flask) in titration experiment.

In this case , NaOH is titrant whose concentration is unknown.

`M_1=\text{molarity of titre}` ,
`M_2=\text{molarity of NaOH}`

`V_1=\text{volume of titre}` ,
`V_2=\text{volume of NaOH}`

`M_1V_1=M_2V_2`

`M_2=(M_1V_1)/(V_2)`....(1)

According to question a chemist overshoots the end point and adds to much of NaOH solution, which means increase in the value of
`V_2`.

Then the value of
`M_2` in equation (1), will get lowered , which means that the concentration of NaOH was lower than that of the actual value. Hence underestimated concentration of NaOH.