Question

Twelve grams of gas occupies 14.5 liters at a pressure of 52.0cm Hg. What is the volume when the pressure has increased to 85.0cm Hg?

Answer 1

8.87 L.

Step-by-step explanation:

From the question given above, the following data were obtained:

Mass (m) of gas = 12 g

Initial volume (V₁) = 14.5 L

Initial pressure (P₁) = 52 cmHg

Final pressure (P₂) = 85 cmHg

Final volume (V₂) =?

The final volume of the gas can be obtained by using the Boyle's Las equation as illustrated below:

P₁V₁ = P₂V₂

52 × 14.5 = 85 × V₂

754 = 85 × V₂

Divide both side by 85

V₂ = 754 / 85

V₂ = 8.87 L

Thus the volume of the gas will be 8.87 L