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One number is eight less than the second number. Twice the first is 9 more than 3 times the second. Find the numbers

User AlexFZ
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3 votes

Answer:

-49/3 and -25/3

Explanation:

Let the numbers be represented by f and s (first and second). Then f = s - 8. Also, 2f = 3s + 9. Solve this system for f and s:

Substituting s - 8 for f in the 2nd equation, above, yields

2(s - 8) = 3s + 9, or 2s - 16 = 3s + 9. Then 3s = -25, and s = -25/3. The first number is then f = s - 8, or f = -25/3 - 8, or f = -49/3.



User Tarken
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