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20x^2-30=4x solve for x

User Abagmut
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2 Answers

0 votes
mmmm let me think about it
User Dusktreader
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6 votes

Answer:

x=1.3288 or -1.1288

Explanation:

Given
20x^(2)-30=4x

Subtract 4x from both sides


20x^(2)-4x-30=0

Since we can factor out 2 from whole equation, let's factor out 2.


2(10x^(2)-2x-15)=0

Divide with 2 on both sides


10x^(2)-2x-15=0

We got the quadratic equation, we can solve for x using quadratic formula.


x=\frac{-b\pm\sqrt{b^(2)-4ac} } {2a}


x=\frac{2\pm\sqrt{2^(2)-4X10X(-15)} } {2X10}


x=(2\pm√(604) )/(20)


x=(2\pm2√(151))/(20)


x=1.3288or-1.1288


User ZaSter
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