162k views
2 votes
Graph f(x)= -0.25x+4
HELP ASAP PLEASE!!!

Graph f(x)= -0.25x+4 HELP ASAP PLEASE!!!-example-1

2 Answers

4 votes

Answer:

Shown below

Explanation:

-0.25/1x is your rise over run, 4 is your “starting point”

Graph f(x)= -0.25x+4 HELP ASAP PLEASE!!!-example-1
User RmLuma
by
9.4k points
5 votes

Answer:

Explanation:

1) Since this function is f(x)=mx+b, whose rule is:


f(x)=-0.25x+4

2) Then this parameter m is a negative one, the line is a decreasing one (from upper left to lower right). Then Let's choose three random values for x, and plug it in the function, to get y values. Let x, be 0,1,2.

The parameter b is 4 then the line crosses the y-axis in point (0,4).

3) Plugging it in, goes:


f(x)=-0.25x+4\Rightarrow f(0)=-0.25(0)+4\Rightarrow f(0)=4\\f(1)=-0.25(1)+4\Rightarrow f(1)=-0.25(1)+4\Rightarrow f(1)=3.75\Rightarrow f(2)=-0.25(2)+4\Rightarrow f(2)=3.50

As we have three coordinate points, we can trace a line:

(0,4),(1,3.75),(2,3.5)

Graph f(x)= -0.25x+4 HELP ASAP PLEASE!!!-example-1
User Siyu Song
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories