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Graph f(x)= -0.25x+4
HELP ASAP PLEASE!!!

Graph f(x)= -0.25x+4 HELP ASAP PLEASE!!!-example-1

2 Answers

4 votes

Answer:

Shown below

Explanation:

-0.25/1x is your rise over run, 4 is your “starting point”

Graph f(x)= -0.25x+4 HELP ASAP PLEASE!!!-example-1
User RmLuma
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5 votes

Answer:

Explanation:

1) Since this function is f(x)=mx+b, whose rule is:


f(x)=-0.25x+4

2) Then this parameter m is a negative one, the line is a decreasing one (from upper left to lower right). Then Let's choose three random values for x, and plug it in the function, to get y values. Let x, be 0,1,2.

The parameter b is 4 then the line crosses the y-axis in point (0,4).

3) Plugging it in, goes:


f(x)=-0.25x+4\Rightarrow f(0)=-0.25(0)+4\Rightarrow f(0)=4\\f(1)=-0.25(1)+4\Rightarrow f(1)=-0.25(1)+4\Rightarrow f(1)=3.75\Rightarrow f(2)=-0.25(2)+4\Rightarrow f(2)=3.50

As we have three coordinate points, we can trace a line:

(0,4),(1,3.75),(2,3.5)

Graph f(x)= -0.25x+4 HELP ASAP PLEASE!!!-example-1
User Siyu Song
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5.1k points