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If CE = 3x - 10 and EA = 2x + 1, then CA=

User Eclewlow
by
5.2k points

2 Answers

13 votes

Answer:

it is 46

Explanation:

First you need to solve.. So put 3x - 10 and 2x + 1 together as one equation.

It should look like this:

3x - 10 = 2x + 1

Now you just need to solve it.

1) First you add 10 on both sides.

3x - 10 = 2x + 1

+ 10 = + 10

------------------------

3x = 2x + 11

2) Then you subtract 2x on both sides.

3x = 2x + 11

- 2x =- 2x + 11

-------------------------

x = 11

3) Now you plug in 11 for x.

3x - 10 = 2x + 1

Like this:

3(11) - 10 = 2(11) + 1

33 - 10 = 22 + 1

23 =23

So C to E and E to A = 23

To get from C to A just add 23 + 23 which is 46. And that is ur answer.

you can slove this in this way if want more explansion ask me

User Amit Bhagat
by
5.4k points
13 votes

Answer:

46

Explanation:

First you need to solve.. So put 3x - 10 and 2x + 1 together as one equation.

It should look like this:

3x - 10 = 2x + 1

Now you just need to solve it.

1) First you add 10 on both sides.

3x - 10 = 2x + 1

+ 10 = + 10

------------------------

3x = 2x + 11

2) Then you subtract 2x on both sides.

3x = 2x + 11

- 2x =- 2x + 11

-------------------------

x = 11

3) Now you plug in 11 for x.

3x - 10 = 2x + 1

Like this:

3(11) - 10 = 2(11) + 1

33 - 10 = 22 + 1

23 =23

So C to E and E to A = 23

To get from C to A just add 23 + 23 which is 46. And that is ur answer.

User Yurii Halapup
by
4.6k points