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What is the value of the range of the function f(x) =2x2-3x+8 for the domain value3?

User Wivlaro
by
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2 Answers

3 votes

Answer

17


Step-by-step explanation

The range of a function is the value resulting from the possible independent variable x. It is the value of y in a function for any given independent variable.

f(x) =2x²-3x+8

When the domain = 3

f(x) = 2(3)² - 3(3) + 8

= 2×9 - 3×3 + 8

= 18 - 9 + 8

= 17

User Anthony McGrath
by
8.5k points
4 votes

Given the function
f(x)=2x^2-3x+8.

For the domain value x=3 you should find f(3). With this aim substitute instead x the value 3 into the function expression:


f(3)=2\cdot 3^2-3\cdot 3+8=18-9+8=17.

Answer: the value of the range f(3) is 17.

User Raman Mishra
by
8.6k points
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