Question

What is the value of the range of the function f(x) =2x2-3x+8 for the domain value3?

Answer 1

17

Step-by-step explanation

The range of a function is the value resulting from the possible independent variable x. It is the value of y in a function for any given independent variable.

f(x) =2x²-3x+8

When the domain = 3

f(x) = 2(3)² - 3(3) + 8

= 2×9 - 3×3 + 8

= 18 - 9 + 8

= 17

Answer 2

Given the function
`f(x)=2x^2-3x+8.`

For the domain value x=3 you should find f(3). With this aim substitute instead x the value 3 into the function expression:

`f(3)=2\cdot 3^2-3\cdot 3+8=18-9+8=17.`

Answer: the value of the range f(3) is 17.