Question

What is the slope of a line with the eqation of 4×+5y=5

Answer 1

to the risk of sounding a bit redundant.

`\bf 4x+5y=5\implies 5y=-4x+5\implies y=\cfrac{-4x+5}{5}\\\\\\\stackrel{\textit{distributing the denominator}}{y=\cfrac{-4x}{5}+\cfrac{5}{5}}\implies \stackrel{slope}{y=\stackrel{\downarrow }{-\cfrac{4}{5}}x}+1\impliedby \begin{array}ll\cline{1-1}slope-intercept~form\\\cline{1-1}\\y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}}\\\\\cline{1-1}\end{array}`

Answer 2

- 4/5x

Explanation:

So, this is a simple thing as long as you convert it into slope-int form. So, I am guessing from the question that the equation is

4x + 5y = 5

From here, you have to isolate y and leave all of the other variable by themselves. So, first you would subtract 4x from both sides and that leaves you with

5y = 5 -4x

Then, to isolate 5, you would divide 5 by both sides to get

y = 1- 4/5x

Now, you would put this is slope intercept form: y = mx + b to get

y = - 4/5 x + 1

Now, you can see that the slope is - 4/5x

Hope I helped!!!!!