Question

Consider the polynomial 16x2 - 1 what is the value of ac what is the value of b

Answer 1

the answer is

-16

0

-4and4

(4x-1)(4x+1)

Answer 2

ac= -16

b=0

`(4x+1)(4x-1)`

Explanation:

`16x^2 -1`

WE write the given polynomial in standard form ax^2 + bx+c

there is no x term so we include 0x

the given expression becomes

`16x^2+0x-1`

The value of a= 16 , b= 0 and c=-1

`ac= a*c = 16 * (-1) = -16`

The value of b = 0

Two number to multiply to get ac = -16 are 4 and -4

When we add two numbers we will get

-4 + 4= 0

using factors -4 and 4 , the expression becomes

`16x^2-4x+4x-1`

`(16x^2-4x)+(4x-1)`

Factor out GCF

`4x(4x-1)+1(4x-1)`

`(4x+1)(4x-1)` is the factored form