208k views
2 votes
Some newly discovered vine has leaves that have a length that is normally distributed with mean 3 units, and standard deviation .2 (2/10). What percent of the leaves should be shorter than 3.5 units long?

1 Answer

6 votes


\text{ Answer: }P(Z<2.5)=0.99379=99.37\%

Explanation:

Since we have given that

Mean =3 units

Standard deviation =0.2

Using normal distribution, we need to find the percent of the leaves should be shorter than 3.5 units long,


P(Z<(X-\mu)/(\sigma))=P(Z<(3.5-3)/(0.2))=P(Z<2.5)

Now, using the normal distribution table,


P(Z<2.5)=0.99379 \\=99.37\%

User Brian Hawkins
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories