Question

Some newly discovered vine has leaves that have a length that is normally distributed with mean 3 units, and standard deviation .2 (2/10). What percent of the leaves should be shorter than 3.5 units long?

Answer 1

`\text{ Answer: }P(Z<2.5)=0.99379=99.37\%`

Explanation:

Since we have given that

Mean =3 units

Standard deviation =0.2

Using normal distribution, we need to find the percent of the leaves should be shorter than 3.5 units long,

`P(Z<(X-\mu)/(\sigma))=P(Z<(3.5-3)/(0.2))=P(Z<2.5)`

Now, using the normal distribution table,

`P(Z<2.5)=0.99379 \\=99.37\%`