Answer:
1) AB/EF = BC/FG = CD/GH = AD/EH = 2/3
2) ABC is congruent to EFG.
BCD is congruent to FGH.
ADC is congruent to EHG.
DAB is congruent to HEF.
3) AB = 3DC. Since GH = 6:
CD/6 = 2/3, so CD = 4 and AB = 12.
12/EF = 2/3, so EF = 18.
AD = BC = 8
8/EH = 2/3, so EH = FG = 12
Perimeter of ABCD = 12 + 8 + 4 + 8 = 32
Perimeter of EFGH = (3/2)(32) = 48