Question

Help me with math please!!

Answer 1

1) AB/EF = BC/FG = CD/GH = AD/EH = 2/3

2) ABC is congruent to EFG.

BCD is congruent to FGH.

ADC is congruent to EHG.

DAB is congruent to HEF.

3) AB = 3DC. Since GH = 6:

CD/6 = 2/3, so CD = 4 and AB = 12.

12/EF = 2/3, so EF = 18.

AD = BC = 8

8/EH = 2/3, so EH = FG = 12

Perimeter of ABCD = 12 + 8 + 4 + 8 = 32

Perimeter of EFGH = (3/2)(32) = 48