Question

Refer

to the rectangle at the right. Suppose the side lengths
are doubled.
a.
Find the percent of change
in the perimeter.
in the area.
b. Find the percent of change

Answer 1

Answer:
400% area and 200% perimeter
Explanation:
Given is a picture of a rectangle. (i.e. opposite sides are equal and all angles equal to 90 degrees)
We know for any rectangle with length I and
width, w
Area of rectangle = Iw and
Perimeter of rectangle = 2(1+w)
Suppose the side lengths are doubled
Now length = 21 and width = 2w
New Area= 2l * 2w
= 4lw
i.e. 400% times is the new area.
New perimeter = 2(2l + 2w) = 4(l + w)

New perimeter is 200% times the old perimeter.