Question

in a triangle one interior angle is 58 degrees bigger than the original interior angle the third angle is 37° larger than three times the original interior angle

Answer 1

`\text{ Answer: original angle will be }17\textdegree\\\\\text{ second angle will be }x+58\textdegree=17+58=75\textdegree\\\\\text{ third angle will be } 3x+37=3* 17+37=88\textdegree`

Explanation:

Let original interior angle be x

Let second interior angle be x+58

Let third interior angle be 3x+37

As we know that

`\text{sum of three angles in triangle is 180\textdegree}`

So, we can use this

`x+x+58\textdegree+3x+37\textdegree=180\textdegree\\\\5x+95\textdegree=180\textdegree\\\\5x=180\textdegree-95\textdegree\\\\5x=85\textdegree\\\\x=(85)/(5)\\\\x=17\textdegree`

So, each angle will be

`\text{ original angle will be }17\textdegree\\\\\text{ second angle will be }x+58\textdegree=17+58=75\textdegree\\\\\text{ third angle will be } 3x+37=3* 17+37=88\textdegree`