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Using the discriminant, determine the number of real solutions.

2x^2+7x-15=0

- no real solutions
-one real solution
-two real solutions

User Te Ko
by
7.7k points

2 Answers

3 votes

Answer:

two real solutions

Explanation:


User Drussey
by
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2 votes

Answer:

Since discriminant is positive, therefore, the given quadratic equation has two real solutions. Correct answer is the last option.

Explanation:

We have been given a quadratic equation and we need to figure out the number of real solutions of the equation.


2x^(2)+7x-15=0

We know that discriminant of a general quadratic equation
ax^(2)+bx+c=0 is given by
D=b^(2)-4ac

For the given quadratic equation
2x^(2)+7x-15=0, we have
a=2,b=7,c=-15. Upon substituting these values in the formula for discriminant, we get:


D=7^(2)-4(2)(-15)


D=49+120


D=169

Since discriminant is a positive number, therefore, the given quadratic equation has two real solutions. Hence, the last option is the correct answer.

User Plalx
by
7.6k points

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