Question

Given the following information:

Fish tank is: 15 inches high x .075 m wide x 30 cm long
Density of water of 1 g/cm3
1 cm3 is equal to 1 mL
D=M/V
Calculate the mass of the water, in grams, the Fish tank can hold.

You must show all conversions and work for full credit.

Answer 1

8572.5 grams of the water will fish tank can hold.

Step-by-step explanation:

Volume of the fish tank = V

Length of fish tank = l = 30 cm

Width of fish tank = w = 0.075 m = 7.5 cm

1 m = 100 cm

Length of fish tank = h = 15 inches = 38.1 cm

1 inch = 2.54 cm

`V=l* w* h=30 cm* 0.075 cm* 38.1 cm=85.725 cm^3`

Volume of fish tank = Volume of water = v =
`8572.5 cm^3`

Mass of water in the tank = m

Density of the water
`d= 1 g/cm^3`

`D=(m)/(v)`

`m=d* v=1 g/cm^3* 8572.5 cm^3=8572.5 g`

8572.5 grams of the water will fish tank can hold.

Answer 2

Step by Step Explanation

From the question,
the dimensions of the tank are;

L = 30 cm, way =0.075m and H = 15 cm

The density of water is given as

`D = 1g {cm}^( - 3)`

The unit of density given in the question means that the mass of the water is in grams and the volume should also be in

`{cm}^(3)`

To find the volume of the water, we first convert the units of dimensions given in inches and metres to centimetres


`1 inch = 2.54 cm`

This implies that ,


`H=15 inches=15×2.54cm=38.1cm`

Also,


`100cm=1m`

This implies that,

`w= (0.075)/(100 ) = 7.5 * {10}^( - 4) cm`

Now, the volume of water in the tank can hold, can be found from the relation;


`V=L* W* H`

This implies that,


`v = 30cm * (7.5 * {10}^( - 4) )cm * 38.1cm`


`v = 0.857 {cm}^(3) \: to \: 3 \: d.p`

Finally, we can calculate the mass of the water from the relation given;


`D=(M)/(V)`

This in implies that


`1g {cm}^( - 3) = \frac{m}{0.857 {cm}^(3) }`

`m = 1g {cm}^( - 3) * 0.857 {cm}^(3)`

`m = 0.857g`


Hence the fish tank can hold 0.857g water.