Question

Special Right Triangles

Answer 1

first option

Explanation:

Using the sine/ cosine ratios in the right triangle and the exact values

sin30° =
`(1)/(2)` , cos30° =
`(√(3) )/(2)`

sin30° =
`(opposite)/(hypotenuse)` =
`(x)/(32)` =
`(1)/(2)` ( cross- multiply )

2x = 32 ( divide both sides by 2 )

x = 16

----------------------------------------------------------

cos30° =
`(adjacent)/(hypotenuse)` =
`(y)/(32)` =
`(√(3) )/(2)` ( cross- multiply )

2y = 32
`√(3)` ( divide both sides by 2 )

y = 16
`√(3)`