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PLEASE HELP QUICK!! !!20 POINTS!!

1. Refer to the equation y = 1/3 x + 2

(a)Create a table of x, y values for 4 ordered pairs. Tip: choose an x, then find y four times. Use “easy numbers”, like x = 0, 3 (gets rid of fraction), or -3

User Mchfrnc
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The final table is in the attached picture.

Before beginning, you should note that:

To get rid of a fraction, this fraction should be multiplied that is equal to or is a multiple of its denominator.

This means that:


(1)/(y) * ay = a

Now, for the given:

We have the equation:
y = (1)/(3) x + 2

The denominator of the fraction is 3, therefore to get rid of it we will need x to be a 3 or a multiple of 3.

Let's consider the x values to be -3, 0, 3 and 6.

For x = -3:
y = (1)/(3) (-3) + 2 = -3 + 2 = -1 .....>First order pair is (-3,-1)

For x = 0:
y = (1)/(3) (0) + 2 = 0 + 2 = 2 .....> Second order pair is (0,2)

For x = 3:
y = (1)/(3) (3) + 2 = 1 + 2 = 3 .....> Third order pair is (3,3)

For x = 6:
y = (1)/(3) (6) + 2 = 2 + 2 = 4 .....> Fourth order pair is (6,4)

Hope this helps :)

PLEASE HELP QUICK!! !!20 POINTS!! 1. Refer to the equation y = 1/3 x + 2 (a)Create-example-1
User Padix Key
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