Question

MATH PLEASE HELP!

Identify the vertex and the y-intercept of Y=-2(x+3)^2+2the graph of the function .
A.vertex: (−3, 2); y-intercept: −16
B.vertex: (−3, −2); y-intercept: 11
C.vertex: (3, 2); y-intercept: −16
D. vertex: (3, −2); y-intercept: −18

Identify the vertex and the y-intercept of the graph of the function Y=-2(x+2)^2+2

A.vertex: (−2, 2); y-intercept: −6


B.vertex: (2, 2); y-intercept: −6


C. vertex: (−2, −2); y-intercept: 6


D. vertex: (2, −2); y-intercept: −8

Answer 1

A

Explanation:

Answer 2

A and A

the equation of a parabola in vertex form is

y = a(x - h)² + k

where ( h, k ) are the coordinates of the vertex and a is a multiplier

y = - 2(x + 3)² + 2 is in this form

with vertex = ( - 3, 2)

To find the y-intercept let x = 0

y = - 2(3)² + 2 = - 18 + 2 = - 16

Similarly

y = - 2(x + 2)² + 2 is in vertex form

vertex = ( - 2 , 2)

x = 0 : y = - 2(2)² + 2 = - 8 + 2 = - 6 ← y- intercept