Question

Math! Help me out on one of these?

Answer 1

(23) x = 800 × tan70°

using the tan ratio in the right triangle

tan 70° =
`(x)/(800)`

⇒ x = 800 × tan 70°

(24) using the tan ratio in the right triangle

tan80° =
`(d)/(30)`

⇒ d = 30 × tan80°

(25)
`(5.6)/(2)` =
`(h)/(6)` ( h is the height of the cross )

using similar triangles, with 2yards = 6 feet

Answer 2

#23) in reference to the given angle, which sides are given? opposite & adjacent

tan θ =
`(opposite)/(adjacent)`

tan 70° =
`(x)/(800)`

800 tan 70° = x

2,197.98 = x

Answer: 2,198

#24) in reference to the given angle, which sides are given? opposite & adjacent

tan θ =
`(opposite)/(adjacent)`

tan 80° =
`(d)/(30)`

30 tan 80° = x

170.138 = x

Answer: 170 ft

#26) first convert everything into the same units. I am going to use feet

5 ft 6 inches = 5.5 ft

2 yards = 6 ft

Next, set up a proportion, cross multiply, and solve for the variable

`(height(boy))/(shadow (boy)) = (height(cross))/(shadow (cross))`

`(5.5)/(2) = (x)/(6)`

5.5(6) = 2(x)

`(5.5(6))/(2) = x`

5.5(3) = x

16.5 = x

Answer: 16.5 ft